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Alternate way: Find 1+2+3+... +(n-1)+n via "polynomial degree 2"

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logic: Show p→q ≡¬ p∨q

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1st way: exp ∫(e^x)/x (1+x log(x)) dx

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Swinburne U 2nd way: e^(-e^x) e^x dx

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MP 2000 Hindustan: Evaluate ∫(tan(x)+cot(x))^2 dx

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1st/2 parts stat: SLR ∑ŷk = ∑yk where k=1,n

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AI 2008 Hindustan 2nd/2 ways: Evaluate trig integral ∫2cos(x)/(3 sin^3(x)) dx

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2nd way: integral ∫ log √x(x^n) dx

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2 ways: The following measurements were taken by an antique dealer as he weighted to the ...

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