#17 2022 MIT Integration Bee Qualifying Exam

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2nd way: Evaluate integral ∫x^2/√(19-x^2) dx

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2nd way: Evaluate integral ∫x^2/√(19-x^2) dx

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Solve the following differential equation cos^2(x)dy/dx +y = tan(x)

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Solve the following differential equation cos^2(x)dy/dx +y = tan(x)

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Alternate way: Find 1+2+3+... +(n-1)+n via "polynomial degree 2"

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Alternate way: Find 1+2+3+... +(n-1)+n via "polynomial degree 2"

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1st way: exp ∫(e^x)/x (1+x log(x)) dx

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1st way: exp ∫(e^x)/x (1+x log(x)) dx

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2nd way: integral ∫ log √x(x^n) dx

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2nd way: integral ∫ log √x(x^n) dx

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MP 8,93,96,97,99 Hindustan: Evaluate ∫ sec(x)/(sec(x)-tan(x)) dx

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MP 8,93,96,97,99 Hindustan: Evaluate ∫ sec(x)/(sec(x)-tan(x)) dx

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AI 2008 Hindustan: Evaluate integral ∫ 2/3 cos(x)/sin^2(x) dx

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AI 2008 Hindustan: Evaluate integral ∫ 2/3 cos(x)/sin^2(x) dx

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CBSE 2000 Hindustan: integral (1+tan(x))/(x+log(sec(x)) dx

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CBSE 2000 Hindustan: integral (1+tan(x))/(x+log(sec(x)) dx

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Pantun Melayu [Buah cempedak di luar pagar]

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Pantun Melayu [Buah cempedak di luar pagar]

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Pantun Melayu [Pulau Pandan Jauh Ke Tengah]

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Pantun Melayu [Pulau Pandan Jauh Ke Tengah]

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2nd way: ∫(x+3)/(x^2+6x)^2 dx vs ∫(x+3)(x^2+6x)^2 dx

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2nd way: ∫(x+3)/(x^2+6x)^2 dx vs ∫(x+3)(x^2+6x)^2 dx

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2nd way: integral ∫x^2 √(x^3+1) dx vs ∫x^3 √(x^3+1) dx

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2nd way: integral ∫x^2 √(x^3+1) dx vs ∫x^3 √(x^3+1) dx

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2nd way: derivative (x/a)^n/(n-1) + (y/b)^n/(n-1) = 1

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2nd way: derivative (x/a)^n/(n-1) + (y/b)^n/(n-1) = 1

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2nd way: ∫cos(x)/√(sin^2(x)+4sin(x)+3) dx

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2nd way: ∫cos(x)/√(sin^2(x)+4sin(x)+3) dx

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derivative If y=e^(a arc sin(x)), prove that (1-x^2)y2 - xy1 = a^2y.

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derivative If y=e^(a arc sin(x)), prove that (1-x^2)y2 - xy1 = a^2y.

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2nd way: ∫1/(√(x-α)(x-β)) dx

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2nd way: ∫1/(√(x-α)(x-β)) dx

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Screen Recording 2023-12-07 at 2.04.49 AM

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Screen Recording 2023-12-07 at 2.04.49 AM

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U North Texas Integration Bee 2nd way: x^2/√(x-1) dx

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U North Texas Integration Bee 2nd way: x^2/√(x-1) dx

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