exp integral ∫(1+e^x)/(1-e^x) dx

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1st way: exp ∫(e^x)/x (1+x log(x)) dx

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Alternate way: Find 1+2+3+... +(n-1)+n via "polynomial degree 2"

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logic: tautology (¬p→q)∧(¬p→¬q) →p

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Screen Recording 2024-05-18 at 12.32.05 AM

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Screen Recording 2024-05-12 at 10.20.08 PM

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#Screen Recording 2024-05-13 at 10.52.38 PM

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